The values of the frequency of the generator, the capacitance, inductance, and i
ID: 1634050 • Letter: T
Question
The values of the frequency of the generator, the capacitance, inductance, and impedance of the circuit are given to the right of the along with the runs current flowing in the circuit. F = 600 Hz C = 1 mu F L = 0.14 H I = 0.15 A Z = 328 Ohm What is the resistance R of this circuit? (a) R = 632 Ohm (b) R = 532 Ohm (c) R = 407 Ohm (d) R = 197 Ohm (e) R = 96 Ohm What is the rms voltage of the generator? (a) 49.2 V (b) 24.5 V (c) 11.6 V The frequency at which this circuit is operating is (a) below the resonant frequency. (b) above the resonant frequency. Calculate V_c the rms voltage across the capacitor. (a) V_c = 11.6 V (b) V_c = 24.5 V (c) V_c = 39.8 V (d) V_c = 49.2 V (e) V_c = 78.6 V If the frequency of the AC source is set to the circuit's resonant frequency, the current provided by the AC source will be minimized. (a) True (b) FalseExplanation / Answer
7.
Z^2 = R^2 + (XL - Xc)^2
R = sqrt (Z^2 - (XL - Xc)^2)
XL = w*L = 2*pi*f*L = 2*pi*600*0.14 = 527.78 ohm
Xc = 1/wC = 1/(2*pi*f*C) = 1/(2*pi*600*1*10^-6) = 265.26 ohm
R = sqrt (328^2 - (527.78 - 265.26)^2) = 196.64 ohm
Correct option is D.
8.
Vrms = irms*Z
Vrms = 0.15*328 = 49.2 V
Correct option is A.
9.
resonance frequency will be:
fr = 1/(2*pi*sqrt (LC))
fr = 1/(2*pi*sqrt (0.14*1*10^-6))
fr = 425.36 Hz
f = 600 Hz
So, circuit is operating above the resonance frequency.
Correct option is B.
10.
Vc = ic*Xc
Vc = 0.15*265.26 = 39.8 V
Correct option is C.
11.
V = i*Z
i = V/Z
since current is inversely proportional to impedance, so at resonance frequency impedance will be minimum, and current will be maximum.
given statement is false.
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