It is said that C 4 H 10 (NO2) 2 +O 2 ---> CO 2 + N 2 +H 2 0, and that H c C4H10

Question

It is said that C4H10(NO2)2 +O2 ---> CO2 + N2 +H20, and that Hc C4H10(NO2)2 =-528.3kJ/mol. I've balanced the equation:2C4H10(NO2)2 + 9O2---> 8CO2 + 2N2 + 10H20 , butwhat would the H of this reaction be? Would you have tomultiply -528.3kJ/mol by 2 since there are two moles ofC4H10(NO2)2 ? It is said that C4H10(NO2)2 +O2 ---> CO2 + N2 +H20, and that Hc C4H10(NO2)2 =-528.3kJ/mol. I've balanced the equation:2C4H10(NO2)2 + 9O2---> 8CO2 + 2N2 + 10H20 , butwhat would the H of this reaction be? Would you have tomultiply -528.3kJ/mol by 2 since there are two moles ofC4H10(NO2)2 ?

Explanation / Answer

H (C4H10 (NO2)2) = -528 kJ/mol This is the enthalpy of formation for the compoundabove. 2C4H10(NO2)2 + 9O2---> 8CO2 + 2N2 + 10H20 H (reaction) = H products - H rectants                      = [ 8 (Hf(CO2)) + 2 (Hf(N2)) + 10 (Hf (H2O))]                                                                   -  [ 2(Hf(C4H10 (NO2)2)) + 9 (Hf (O2)) ] Substitute the values of Hf from the appendix or tablesat the end of your book for each of the compounds along with thevalue for C4 H10 (NO2)2 and simplify to get the answer.

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