4. What mass of bromine (Br 2 ) is produced whenflourine reacts with 1.72 g of p

Question

4. What mass of bromine (Br2) is produced whenflourine reacts with 1.72 g of potassium bromide? 6. What mass of sodium chloride is produced when chlorinereacts with 0.29 g of sodium iodide? My teacher said we needed to write an equation in order tosolve the two above questions I am confused, I know how to solveones with an equation, but not this... ______________ 7. How many grams of lead(II) iodide are produced from 6.0moles of NaI according to the following equation:                Pb(NO3)2+ 2 NaI ---> 2 NaNO3 + PbI2 8. Consider the following equation:          2AlBr3 + 3 Cl2 --->3Br2 + 2 AlCl3 How many grams of aluminum chloride will be produced from 92grams of CI2? ___________________________________________________________________ 4. Identify the limiting reactant when 3.6 mol of Al reactswith 5.3 mol of Cl2 to produce AlCl3. 5. Identify the limiting reactant when 14.5 mol of P reactswith 18.0 mol of O2 to produceP4O10 6. Identify the limiting reactant when 1.22 g of O2reacts with 1.05 g of H2 to produce water. 7. Identify the limiting reactant when 4.68 g of Fe reactswith 2.88 g of S to produce FeS.
I will rate yousaparately if you answer it in different posts!THANKS!!! I don't have time to post it one by one! Thanks I 4. What mass of bromine (Br2) is produced whenflourine reacts with 1.72 g of potassium bromide? 6. What mass of sodium chloride is produced when chlorinereacts with 0.29 g of sodium iodide? My teacher said we needed to write an equation in order tosolve the two above questions I am confused, I know how to solveones with an equation, but not this... ______________ 7. How many grams of lead(II) iodide are produced from 6.0moles of NaI according to the following equation:                Pb(NO3)2+ 2 NaI ---> 2 NaNO3 + PbI2 8. Consider the following equation:          2AlBr3 + 3 Cl2 --->3Br2 + 2 AlCl3 How many grams of aluminum chloride will be produced from 92grams of CI2? ___________________________________________________________________ 4. Identify the limiting reactant when 3.6 mol of Al reactswith 5.3 mol of Cl2 to produce AlCl3. 5. Identify the limiting reactant when 14.5 mol of P reactswith 18.0 mol of O2 to produceP4O10 6. Identify the limiting reactant when 1.22 g of O2reacts with 1.05 g of H2 to produce water. 7. Identify the limiting reactant when 4.68 g of Fe reactswith 2.88 g of S to produce FeS.
I will rate yousaparately if you answer it in different posts!THANKS!!! I don't have time to post it one by one! Thanks I don't have time to post it one by one! Thanks I

Explanation / Answer

How many grams of lead(II) iodide are produced from 6.0 molesof NaI according to the following equation:                Pb(NO3)2+ 2 NaI ---> 2 NaNO3 + PbI2                Pb(NO3)2+ 2 NaI ---> 2 NaNO3 + PbI2 6 mol NaI * (1 mol PbI2 / 2 mol NaI)(148.89 g /1 mol NaI) =446.67 g NaI Consider the following equation:          2AlBr3 + 3 Cl2 --->3Br2 + 2 AlCl3 How many grams of aluminum chloride will be produced from 92grams of CI2
92 g Cl2 * (1 mol Cl2 / 70.9 g)(2 mol AlCl3/3 mol Cl2)(133.34 gAlCl3 / 1mol AlCl3) = 113.6 g AlCl3          2AlBr3 + 3 Cl2 --->3Br2 + 2 AlCl3 How many grams of aluminum chloride will be produced from 92grams of CI2 4. Identify the limiting reactant when 3.6 mol of Al reactswith 5.3 mol of Cl2 to produce AlCl3 Balnced equation 3 Cl2 + 2 Al -> 2 AlCl3 3.6 mol Al *(2 mol AlCl3 / 2 mol Al) -> 3.6 mol AlCl3 3 mol Cl2 * ( 2 mol AlCl3/ 3 Cl 2) -> 2 mol AlCl3 Cl2 is limiting reactant. it yields less alcl3 5. Identify the limiting reactant when 14.5 mol of P reactswith 18.0 mol of O2 to produceP4O10 balanced equation 4 P + 5 O2 -> P4O10 14.5 mol P*(1 mol P4O10 / 4 mol P) = 2.63 mol P4O10 18 mol O2 * ( 1 mol P4O10 / 5 mol O2) = 3.6 mol P4O10 P is limiting becuase it yields lessmoles ofproduct 4. Identify the limiting reactant when 3.6 mol of Al reactswith 5.3 mol of Cl2 to produce AlCl3 Balnced equation 3 Cl2 + 2 Al -> 2 AlCl3 3.6 mol Al *(2 mol AlCl3 / 2 mol Al) -> 3.6 mol AlCl3 3 mol Cl2 * ( 2 mol AlCl3/ 3 Cl 2) -> 2 mol AlCl3 Cl2 is limiting reactant. it yields less alcl3 5. Identify the limiting reactant when 14.5 mol of P reactswith 18.0 mol of O2 to produceP4O10 balanced equation 4 P + 5 O2 -> P4O10 14.5 mol P*(1 mol P4O10 / 4 mol P) = 2.63 mol P4O10 18 mol O2 * ( 1 mol P4O10 / 5 mol O2) = 3.6 mol P4O10 P is limiting becuase it yields lessmoles ofproduct 5. Identify the limiting reactant when 14.5 mol of P reactswith 18.0 mol of O2 to produceP4O10 balanced equation 4 P + 5 O2 -> P4O10 14.5 mol P*(1 mol P4O10 / 4 mol P) = 2.63 mol P4O10 18 mol O2 * ( 1 mol P4O10 / 5 mol O2) = 3.6 mol P4O10 P is limiting becuase it yields lessmoles ofproduct 14.5 mol P*(1 mol P4O10 / 4 mol P) = 2.63 mol P4O10 18 mol O2 * ( 1 mol P4O10 / 5 mol O2) = 3.6 mol P4O10 P is limiting becuase it yields lessmoles ofproduct

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