2 Al(OH) 3 + 3H 2 SO 4 ---> Al 2 (SO 4 ) 3 + 6H 2 O Using the balanced equations

Question

2 Al(OH)3   +   3H2SO4 --->  Al2(SO4)3   + 6H2O

 Using the balanced equations from the reactions above,

determine the following: How many grams ofAl2(SO4)3 are formed from 5 gramsof Al(OH)3? 2 Al(OH)3   +   3H2SO4 --->  Al2(SO4)3   + 6H2O determine the following: How many grams ofAl2(SO4)3 are formed from 5 gramsof Al(OH)3? How many grams ofAl2(SO4)3 are formed from 5 gramsof Al(OH)3? 2 Al(OH)3   +   3H2SO4 --->  Al2(SO4)3   + 6H2O

 Using the balanced equations from the reactions above,

determine the following: How many grams ofAl2(SO4)3 are formed from 5 gramsof Al(OH)3?

Explanation / Answer

n(Al(OH)3) = m/M = 5/78.004 = 0.06410mol n(Al2(SO4)3) = 1/2 xn(Al(OH)3) = 1/2 x 0.0641 = 0.03205mol m(Al2(SO4)3) = nM = 0.03205 x342.14 = 10.97g Hope this helps!

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