The mass of brass sample is 92.6 grams. Putting 92.6 gram sample ofbrass heated

Question

The mass of brass sample is 92.6 grams. Putting 92.6 gram sample ofbrass heated to 70.0&degC into 100 grams of water at20.0&degC raised the temperature of the water to 23.9°C.

Questions:

1) Temperature of Heated Sample
2) Final Temperature of Water (without sample)
3) Temperature Change of Water
4) Specific Heat of Water
5) Heat Gained by Water
6) Heat Lost by Sample... (answer should be in Calories)
7) Temperature Change of Sample.... (answer should be indegrees)
8) Specific Heat of Sample... (answer should be incal/g-°C)

WILL RATE HIGH...

Explanation / Answer

1) Temperature of Heated Sample = 70.0 C

2) Final Temperature of Water (without sample) = 23.9 C
3) Temperature Change of Water = Final - initial temperature                                                   = 23.9 C - 20.0 C                                                    =3.9 C
4) Specific Heat of Water = 1 cal/g.C
5) Heat Gained by Water = Mass * specific heat * temperaturedifference                                        =100 g * 1 cal/g.C * 3.9 C                                       = 390 calories
6) Heat Lost by Sample... (answer should be in Calories) Heat lost by sample is equal to heat gained by water. so heat lost by sample = 390 calories 7) Temperature Change of Sample.... (answer should be indegrees)    Temperature change = 70.0 - 23.9 = 46.1C
8) Specific Heat of Sample... (answer should be incal/g-°C)
Let specific heat of brass be 's' cal/g.C Since heat gained by water = heat lost by sample, 390 calories = 92.6 g * s cal/g.C * 46.1 C So specific heat of sample = 0.0913 cal/g.C

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