The mass of a particular harpy eagle is twice that of a hunted parrot. Suppose t

Question

The mass of a particular harpy eagle is twice that of a hunted parrot. Suppose the parrot is flying north at 16.3 m/s, when the harpy eagle swoops down, grabs the parrot, and flies off. At the instant right before the attack, the harpy eagle is flying toward the parrot at an angle theta= 58.3 degree below the horizontal, and a speed of 41.1 m/s. What is the speed of the harpy eagle immediately after it catches its prey? Number m/s What is the magnitude of the angle, measured from horizontal, at which the harpy eagle is flying immediately after the strike? Number m/s

Explanation / Answer

let the final speed is v

mass of eagle = 2 m

mass of parrot = m

as there is no external force acting during the collision duration

Using consveraiton of momentum

2 m * 39.5 * ( cos(45.1) i + j * sin(45.1)) +m * 17.5 i = 3 m ( v )

3 v = 2* 39.5 * ( cos(45.1) i + j * sin(45.1)) + 17.5 i

v = 24.42 i - 18.65 j m/s

v = sqrt(24.42^2 + 18.65^2) at arctan(-18.65/24.42) degree

v = 30.73 m/s at -37.4 degree

the speed of oh hapry eagle is 30.73 m/s

theta magnitude of angle is 37.4 degree

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