The mass m 1 enters from the left with velocity v 0 and strikes a lighter mass,
ID: 2026694 • Letter: T
Question
The mass m1 enters from the left with velocity v0 and strikes a lighter mass, m2 < m1, where m2 is initially at rest. The collision between the blocks is perfectly elastic. The mass m2 then compresses the spring an amount x. (positive velocities move to the right)
Please Answer in (Greater then, Less then, or equal to)...
Immediately after the collision, the magnitude of the momentum of m2 is ....... the magnitude of the initial momentum of m1.
Immediately after colliding with m2, the velocity of mass m1 is ........... zero.
Thank you for all your help
Explanation / Answer
SOLUTION( 1) Immediately after the collision, is the magnitude of the momentum of m2 greater, equal, or less than the magnitude of the initial momentum of m1?
Answer: greater
This is because m1 rebounds to the left. Therefore, by conservation of momentum, the momentum of m2 must be greater than the initial momentum of m1 so that the total momentum of the system is conserved. ----------------------------------------------------------------------------------------------------------
(2) Immediately after colliding with m2, is the velocity of mass m1 is greater, equal or less than zero?
Ans: greater
m1 rebounds to the left with some non-zero speed. In perfectly elastic collision, the initially moving object comes to rest after collision with a stationary target if both objects are of equal mass. But in this problem, they are not of equal mass.
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