A neon atom emits light at many wavelengths, two of which areat 616.4 and 638.3

Question

A neon atom emits light at many wavelengths, two of which areat 616.4 and 638.3 nm. Both of these transitions are to thesame final state. a) What is the energy difference between the two states foreach transition? b) If a transition between the two higher energy states couldbe observed, what would be the frequency of the light? A neon atom emits light at many wavelengths, two of which areat 616.4 and 638.3 nm. Both of these transitions are to thesame final state. a) What is the energy difference between the two states foreach transition? b) If a transition between the two higher energy states couldbe observed, what would be the frequency of the light?

Explanation / Answer

B) v=c/ v= 2.998x10`8/616.4x 10`-9=4.864x10`14 v=2.998x10`8/638.3x10`-9=4.697x10`14 E=hv E=4.864x10`14 x 6.626x10`-34=3.223 x10`-19 E=4.697x10`14 x 6.626x10`-34=3.112x 10`-19 there is a slight difference in results only by pointsomething the diffrence is 1.11 x 10 ^-20

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