in the presence of a catalyst, methenol, CH3OH, can beprepared by the reaction H

Question

in the presence of a catalyst, methenol, CH3OH, can beprepared by the reaction H2 and CO at high temperature according tothe following equation CO(g) + 2H2(g) produce CH3OH(g) what is the concentration of CH3OH(g) in mol/L ifH2=0.080M, CO=0.025M, and Keq=290 at 700K? in the presence of a catalyst, methenol, CH3OH, can beprepared by the reaction H2 and CO at high temperature according tothe following equation CO(g) + 2H2(g) produce CH3OH(g) what is the concentration of CH3OH(g) in mol/L ifH2=0.080M, CO=0.025M, and Keq=290 at 700K?

Explanation / Answer

Keq equals the concentration of products over theconcentrations of reactants. The coefficient of each speciesindicates the power to which the concentration should be raised inthe Keq equation: CO(g)+2H2(g)CH3OH(g) Keq=[CH3OH]/[CO][H2]2 If you plug in what you are given, you get: 290=[CH3OH]/(0.025)(0.080)2 Using algebra, solve for [CH3OH].

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