4)Given: CH 4 (g) -->2H 2 (g)+C(s) H=74.81KJ/mol CH 4 (g)+2O 2 (g) -->CO 2 +2H 2

Question

4)Given:       CH4(g) -->2H2(g)+C(s)                                 H=74.81KJ/mol       CH4(g)+2O2(g) -->CO2+2H2O(l)               H=-890.37KJ/mol Calculate the H of C(s)+O2(g)-->CO2(g) Given: CH4(g) -->2H2(g)+C(s) Delta H=74.81KJ/mol H2(g)+1/2 O2(g)-->H2O(l) Delta H=-285.83KJ/mol CH4(g)+2O2(g) -->CO2+2H2O(l) Delta H=-890.37KJ/mol Calculate the ?H of C(s)+O2(g)-->CO2(g)

Explanation / Answer

Invert the first equation. Double and invert the second one, ad dthe two together. C + 2H2 + 2H2O > CH4+2H2+ O2 C + 2H2O > CH4 + O2 Add the third equation to the new one. CH4 + 2O2 + C +2H2O > CH4 +O2 + CO2 + 2H2O C + O2 > CO2 Final equation complete. As for H calculations.. H = -74.81 + 571.66 + 890.37 = 1387.22 kJ/mol

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