The thermal decompositon of phosphine (PH 3 ) intophosphorus and hydrogen is a f

Question

The thermal decompositon of phosphine (PH3) intophosphorus and hydrogen is a first-order reaction: 4 PH3(g) P(g) + 6 H2(g) The half-life of the reaction is 35.0 s at 680 degree C. a) Calculate the first-order rate constant for thereaction? b) Calculate the time required for 86.0 percent of thephosphine to decompose? The thermal decompositon of phosphine (PH3) intophosphorus and hydrogen is a first-order reaction: 4 PH3(g) P(g) + 6 H2(g) The half-life of the reaction is 35.0 s at 680 degree C. a) Calculate the first-order rate constant for thereaction? b) Calculate the time required for 86.0 percent of thephosphine to decompose?

Explanation / Answer

a. t1/2 = ln2/k 35 = ln2/k k = .0198 s-1 b. Equation: ln[A] = -kt + ln[A0] Assume initial concentration was 100, if 86% decomposes, the finalconcentration is 14 ln(14) = (-.0198)(t) + ln(100) t = 99.28 sec

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