What mass ( kg ) of the solvent C 6 H 6 shouldbe added with 1240 mL of the solut

Question

What mass ( kg ) of the solvent C6H6 shouldbe added with 1240 mL of the soluteCH3(CH2)4CH3 tomake a solution that is 2.55 mCH3(CH2)4CH3.


Molar Mass (g/mol) CH3(CH2)4CH3 86.18 C6H6 78.11 Density ( kg/L ) CH3(CH2)4CH3 0.6548 C6H6 0.8786 Name/Formula hexane CH3(CH2)4CH3 benzene C6H6 What mass ( kg ) of the solvent C6H6 shouldbe added with 1240 mL of the soluteCH3(CH2)4CH3 tomake a solution that is 2.55 mCH3(CH2)4CH3.


Molar Mass (g/mol) CH3(CH2)4CH3 86.18 C6H6 78.11 Density ( kg/L ) CH3(CH2)4CH3 0.6548 C6H6 0.8786 Name/Formula hexane CH3(CH2)4CH3 benzene C6H6

Explanation / Answer

         molalityof the solution = 2.55 m    volume of solute = 1240mL = 1.24 L density = 0.6548 Kg /L     mass of solute = 1.24 x0.6548 = 0.811952 Kg = 811.952 g         number of moles of solute = (811.952/ 86.18) = 9.42     2.55 = 9.42 / mass of solvent(Kg)     mass of solvent added = (9.42 /2.55) = 3.69 Kg

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