A 5.00 gram sample ofa compound is dissolved in enough water to form 100.0 mL of

Question

A 5.00 gram sample ofa compound is dissolved in enough water to form 100.0 mL ofsolution. This solution has an osmotic pressure of 25.0 torrat 25 C. If it is assumed that each molecule of the solutedissocciates into two particles (in this solvent), what is themolar mass of this solute? 1560 g/mol 18,600 g/mol 37,200 g/mol 74,400 g/mol none of these A 5.00 gram sample ofa compound is dissolved in enough water to form 100.0 mL ofsolution. This solution has an osmotic pressure of 25.0 torrat 25 C. If it is assumed that each molecule of the solutedissocciates into two particles (in this solvent), what is themolar mass of this solute? 1560 g/mol 18,600 g/mol 37,200 g/mol 74,400 g/mol none of these

Explanation / Answer

We Know that :      According to Osmotic Pressure :          = i CRT          25 / 760 atm   = 2 x 5.0 gm / ( M gm / mole x 0.1 L )   x 0.0821 atm-L / mole-K x 298 K          Molecular weight of the solute =   74376.032 gm / mole             The option c is close to the answer.          Collodial dispersion is due to Electrostatic Repulsion it is theproperty of colloidal particles whereas the      others are the phenemenon shownby collodial particles.

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