The addition of a halogen to an alkene is a good way toproduce an alkyl halide i

Question

The addition of a halogen to an alkene is a good way toproduce an alkyl halide in the laboratory. But often, a researcheris interested in adding only one halogen atom to the compound. Insuch a case, a hydrogen halide is used for the addition reaction. (a) If a research student fills a 2.5-L flaskwith 0.24 g gaseous hydrogen chloride and0.44 g of gaseous trans-2-butene, whatmass of the addition product can be made?
___________ g

(b) What is the name of product?
___________

(c) What is the concentration, in molarity, of the product in theflask?
_____________ M
The addition of a halogen to an alkene is a good way toproduce an alkyl halide in the laboratory. But often, a researcheris interested in adding only one halogen atom to the compound. Insuch a case, a hydrogen halide is used for the addition reaction. (a) If a research student fills a 2.5-L flaskwith 0.24 g gaseous hydrogen chloride and0.44 g of gaseous trans-2-butene, whatmass of the addition product can be made?
___________ g

(b) What is the name of product?
___________

(c) What is the concentration, in molarity, of the product in theflask?
_____________ M
(a) If a research student fills a 2.5-L flaskwith 0.24 g gaseous hydrogen chloride and0.44 g of gaseous trans-2-butene, whatmass of the addition product can be made?
___________ g

(b) What is the name of product?
___________

(c) What is the concentration, in molarity, of the product in theflask?
_____________ M

Explanation / Answer

A. First set up the chemical reaction and determine the limitingreagent. Through simple computation it is seen that there is .00658moles of HCl and .007857 moles of butene. Thus the limitingreactant is HCl and we know there is .00658 moles of productproduced. The product (CH3-CHCl-CH2-CH3) weights 92.458 g/mole.Multiply the molar weight by the moles of product and we find thereto be. .6086 grams of product B. 2-Chloro-Butane... But there are many different ways toname chemicals so make sure to use the way that your professorperfers (although the name i gave is one of many correctones). C. Molarity= moles/L    .00658/2.5=.002632M I hope this helps =]

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