1) If 6.02 x 10^23 molecules make up 28.0g of nitrogen, thenwhat is the mass of
ID: 675660 • Letter: 1
Question
1) If 6.02 x 10^23 molecules make up 28.0g of nitrogen, thenwhat is the mass of one molcule of nitrogen? 2) calculate the mass, in grams, of an oxygen atom. If oneoxygen atom has a mass of 16.0 amu, then one amu expressed in gramsis? 3) 0.120 L of NO2 (g) at STP, find the # of molescontained 1) If 6.02 x 10^23 molecules make up 28.0g of nitrogen, thenwhat is the mass of one molcule of nitrogen? 2) calculate the mass, in grams, of an oxygen atom. If oneoxygen atom has a mass of 16.0 amu, then one amu expressed in gramsis? 3) 0.120 L of NO2 (g) at STP, find the # of molescontainedExplanation / Answer
1.) (28.0 g N) / (6.02 x 10^23 molecules N) = 4.65 x 10^-23g/molecules N 4.65 x 10^-23 g/molecules N 2.) oxygen atom = 16 grams (16 grams O) / (6.02 x 10^23 amu O) =2.66 x 10^-23 grams/amu O 3.) (.120 L NO2) x (1 mol O / 22.4 L O) = .0054 mol O since it is STP, there are 22.4 L per mol of oxygen since it is STP, there are 22.4 L per mol of oxygenRelated Questions
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