We are going to trace the following program, i.e. simulate in your head how it w

Question

We are going to trace the following program, i.e. simulate in your head how it would execute on a computer. To help you, a trace table is provided for you to fill.
For each “execution step” of the program, write down in the table the line being executed along with the value of each variable that was modified, the evaluation being performed, and any output that’s being displayed to the console.

1 #include <stdio.h>
2
3 int foobar( int num );
4
5 int main( void )
6 {
7     int y; // y will hold user input
8    
9     printf( "%s", "Enter an int between 1 and 32000: " );
10     scanf( "%d", &y );
11    
12     if ( foobar( y ) ) {
13         printf( "%d, it is! ", y );
14     }
15     else {
16         printf( "%d, it is not! ", y );
17     }
18 }
19
20 int foobar( int num )
21 {
22     size_t i;
23     int bar = 1;
24     int foo = 1;
25    
26     for ( i = 1; i <= 10; i++, bar <<= 1 ) {
27         if ((num&bar)!=0) {
28             foo = 0;
29             break;
30         }
31     }
32     return foo;
33 }

Trace Table to Fill
Feel free to add / remove rows if necessary.

Activity/Evaluation Performed Step Line Variable Values Console Output yi bar foonum 2

Explanation / Answer

Here we are checking value Y.

int y; here Y is input that user will provide.In foobar function size_t = i and we will take i = 1 and

variable int bar = 1;
int foo = 1;

These variable already intialize as 1 then go to next condition that is

bar <<= 1

Condition is satisfie

then go to the check next condition

if ((num&bar)!=0)

Condition is satisfie

check intialization and then return the value.

Step Line y i bar foo num Activity/Evaluation Console output 1 1 1 1 1 0 1 check condition it is! 1 2

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