You have a jar of 1.5 mole/kg sucrose solution at room temperature (25 o C). You
ID: 64132 • Letter: Y
Question
You have a jar of 1.5 mole/kg sucrose solution at room temperature (25oC). You fill a bag with a 0.8 mole/kg sucrose solution. The bag is flexible and is made out of a semipermeable membrane, that is impermeable to sucrose. The bag fits into the jar and is submerged in the solution.
Find the osmotic potential of the solution in the jar?
Based upon Q1, what is the osmotic potential of the bag before osmosis occurs?
What is the initial total water potential of the bag? i.e. before osmosis occurs
Which direction will the water in Q1 move when osmosis occurs? (neither direction as the water would be unable to move, from jar to solution in bag, neither direction as they are in equilibrium, or from the bag to the solution in the jar)
If the bag and jar initially had the same mass of water (1kg), what would the final weight of the water in the bag be after osmosis?
Explanation / Answer
a. Osmotic potential = - mRT
Here - m = moler concentration
R = Gas constant [0.082 mole/molecules]
T = Absolute temperature
so a/c to question OP of jar is -1.5X.082X 298 = -36.654
b.
The difference between the free energy of molecules of pure water and free energy of the solution is called water potential of the system.”
w = s + p + g
g, m is neglesible
Osmotic potential = - mRT
Here - m = moler concentration
R = Gas constant [0.082 mole/molecules]
T = Absolute temperature
so a/c to question OP of bag is -2.5X.082X 298 = -61.09 pascal
c. water will move from jar to bag
due to endoosmosis wt. of bag will increase.
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