PHPO Basa.or Acidic, Neutral? State whether the solution in the first row is aci
ID: 637794 • Letter: P
Question
PHPO Basa.or Acidic, Neutral? State whether the solution in the first row is acidic, basic, or neutral. 2.6 × 10-6 M O acidic O basic 0 neutral 3.92 1.5 × 10-5 M 1.00 Submit Request Answer Part F State whether the solution in the second row is acidic, basic, or neutral. O acidic O basic neutral Request Answer Part Acidic, H,o1OHPH POH Basic, or Neutral? State whether the solution in the third row is acidic, basic, or neutral. 2.6 × 10-6 M O acidic O basic O neutral 3.92 1.5 x 10-M 1.00 Submit Part H State whether the solution in the fourth row is acidic, basic, or neutral. acidic basic neutralExplanation / Answer
Part E
[OH-] = 2.6*10^-6 M
pOH = - log [OH-] = - log (2.6*10^-6)
= 5.86
pH = 14 - pOH = 14 - 5.86 = 8.14
pH > 7 (basic)
pH = - log [H3O+]
[H3O+] = 10^-pH = 10^-8.14 = 7.24 x 10^-9 M
First row is basic
Part F
pH = 3.92
pH < 7 (acidic)
pOH = 14 - pH = 14 - 3.92 = 10.08
pOH = - log [OH-]
[OH-] = 10^-pOH = 10^(-10.08) = 8.32 x 10^-11 M
[H3O+] = 10^-pH = 10^-3.92 = 1.2 x 10^-3 M
Second row is acidic
Part G
[H3O+] = 1.5 x 10^-5 M
pH = - log [H3O+] = - log (1.5 x 10^-5)
pH = 4.82
pH < 7 (acidic)
pOH = 14 - 4.82 = 9.18
[OH-] = 10^-pOH = 10^(-9.18) = 6.61 x 10^-10 M
Third row is acidic
Part H
pOH = 1
[OH-] = 10^-pOH = 10^(-1) = 10^-1 M
pH = 14 - 1 = 13
pH > 7 (basic)
[H3O+] = 10^-pH = 10^-13 M
Fourth row is basic
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