om/myct/itemView?assignmentProblemID-102612133 What is the oxidation state of an

Question

om/myct/itemView?assignmentProblemID-102612133 What is the oxidation state of an individual bromine atom in NaBrO? Express the oxidation state numerically (e.g., +1). View Available Hint(s) Submit Previous Answers x Incorrect, Try Again; 5 attempts remaining ? Part B What is the oxidation state of an individual nitrogen atom in NH2OH? Express the oxidation state numerically (e.g., +1). > View Available Hint(s) Submi in an ion the sum of the oxidation states is equal to the overal lonic charge Note that the sign of the oxidalio ondation state must be considered In OH for example, the oxygen atom has an axidation state of lons

Explanation / Answer

Answer:

Part A:

Given compound is NaBrO3.

Sodium, Na has +1 oxidation state, and Oxygen, O has -2 charge.

Therefore, (+1+Br+(3x-2))=0

Br=6-1=+5 .

The oxidation state of individual Br atom =+5.

Part B:

Given compound is NH2OH

Hydrogen has +1 and O has -2 oxidation state.

Therefore (N+(2x+1)+(1x-2)+(1x+1))=0

N=2-3=-1

The oxidation state of individual N atom=-1.

Part C:

Given compound is PO4^3-

Oxidation state of O=-2.

Therefore, P+(4x-2)=-3

P=-3+8=+5

The oxidation state of individual P atom=+5.

Part D:

Given compound is C2O4^2-

Oxygen has -2 charge

Therefore, 2C+(4x-2)=-2

2C=-2+8=+6

C=+6/2=+3

The oxidation state of individual C=+3.

Please let me know if you have any doubt. Thanks and I hope you like it.

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