1. When did Gregor Mendel perform his experiments with garden peas? a. in the 18
ID: 63458 • Letter: 1
Question
1. When did Gregor Mendel perform his experiments with garden peas?
a. in the 1860s, the same decade as the United States' Civil War
b. in the 1760s, predating the formation of the United States of America
c. in the 1620s, the decade in which William Shakespeare died
d. in the 1720s, the decade in which Bach composed the Brandenburg Concertos
e. in the 1820s, the decade in which Ecuador became independent from Spain
2. Mendel crossed true-breeding plants having yellow peas with plants having green peas. The resulting plants all had yellow peas. An F1 cross resulted in 3/4 of the plants having yellow peas and 1/4 of the plants having green peas. What does this tell you about the alleles for color?
a. yellow is usually the dominant color, but sometimes green can be dominant
b. green is the dominant color
c. yellow is the dominant color
d. yellow is the recessive color
e. the F1 plants must have had some green peas that went unnoticed.
3. A testcross is used to
a. determine if a parent with a dominant trait is heterozygous or homozygous.
b. determine which allele is dominant.
c. determine if the progeny of an experimental cross will get a random assortment of
alleles.
d. prove that an organism is true-breeding.
e. cross an individual with a dominant phenotype with a homozygous dominant individual to prove the alleles are indeed dominant.
4. A parent has a genotype of RrYy. What is the probability of having a gamete with the RY genotype?
a. 1/2
b. 1/4
c. 3/4
d. 1/8
e. 0
5. Which individual established the connection between genes, meiosis, and fertilization?
a. Gregor Mendel
b. Hugo de Vries
c. Carl Correns
d. Erich von Tschermak
e. Walter Sutton
6. Your parents are both heterozygous for the recessive disorder phenylketonuria (PKU). What is the probability that you will have the disorder?
a. 25% regardless of the health of your 3 siblings
b. 50% no matter whether or not you have siblings
c. 75% no matter whether or not you have siblings
d. 100% even if you are an only child
e. 25% but only if your three siblings are healthy.
7. A cross is done between parents with genotypes aaBbCc and aaBbcc. What is the probability that offspring will have the same genotype as the first parent?
a. 1/8
b. 1/4
c. 3/8
d. 3/16
e. 9/16
8. You cross a pink snapdragon (CRCW) with a white snapdragon (CWCW). What percentage of the progeny will be red?
a. 0%
b. 25%
c. 50%
d. 75%
e. 100%
9. Your father has type B blood. Your mother has type O blood. You get tested and learn that your blood is also type O. What does this tell you?
a. You were adopted and your parents didn't tell you.
b. Your mother had a secret affair.
c. Your father's genotype is IBi and your mother's genotype is ii.
d. Your father's genotype is IBIB and your mother's genotype is ii.
e. Your father's genotype is IAIB and your mother's genotype is ii.
10. The different alleles in human blood type are a demonstration of
a. incomplete dominance.
b. codominance.
c. dominance and codominance.
d. dominance and incomplete dominance.
e. dominance, codominance, and incomplete dominance.
11. Mouse pigmentation is subject to epistasis of the B alleles by the d alleles. B (black) is dominant over b (brown). D is dominant over d. Homozygous d is epistatic to the black and brown genes. Given this information, what genotypes give you a white mouse?
a. BBdd
b. Bbdd
c. bbDD
d. bbDd
e. BBdd and Bbdd
12. Linked genes are
a. genes whose effects combine to affect a single characteristic.
b. different alleles of the same gene.
c. genes that affect two different traits and that lead to a 9:3:3:1 phenotype ratio in a dihybrid cross.
d. genes that do not sort independently due to their being physically near each other on the same chromosome.
e. genes on two different chromosomes
13. Exceptions to the principle of independent assortment were discovered and explained by ____ as resulting from genes being physically associated with each other on the same chromosome.
a. Watson
b. Sturtevant
c. Morgan
d. Mendel
e. Crick
14. Genetic studies of an animal show that eye color is controlled by an autosomal gene with the dominant allele (R) for red eye color and the recessive allele (r) for yellow eye color. A second autosomal gene has the dominant allele (T) leading to paws with thumbs while the recessive allele (t) codes for paws without thumbs. The genetic cross RRTT rrtt creates offspring with genotype RrTt. One of those dihybrids is mated in a testcross (RrTt rrtt). Based on the principle of independent assortment the testcross should produce offspring with the phenotype ratio
a. 3 red-eyed with thumbs: 1 yellow-eyed without thumbs.
b. 1 red-eyed with thumbs: 1 yellow-eyed with thumbs: 1 red-eyed without thumbs: 1 yellow-eyed without thumbs.
c.1 red-eyed with thumbs: 1 yellow-eyed without thumbs.
d. 9 red-eyed with thumbs: 3 yellow-eyed with thumbs: 3 red-eyed without thumbs: 1 yellow-eyed without thumbs.
e. 3 yellow-eyed with thumbs: 1 red-eyed without thumbs.
15. Genetic studies of an animal show that eye color is controlled by an autosomal gene with the dominant allele (R) for red eye color and the recessive allele (r) for yellow eye color. A second autosomal gene has the dominant allele (T) leading to paws with thumbs while the recessive allele (t) codes for paws without thumbs. The genetic cross RRTT rrtt creates offspring with genotype RrTt. One of those dihybrids is mated in a testcross (RrTt rrtt). If the two genes are completely linked (no recombination occurs between them), then the testcross should produce offspring with the phenotype ratio
a. 3 red-eyed with thumbs: 1 yellow-eyed without thumbs.
b. 1 red-eyed with thumbs: 1 yellow-eyed with thumbs: 1 red-eyed without thumbs: 1 yellow-eyed without thumbs.
c. 1 red-eyed with thumbs: 1 yellow-eyed without thumbs.
d. 9 red-eyed with thumbs: 3 yellow-eyed with thumbs: 3 red-eyed without thumbs: 1 yellow-eyed without thumbs.
e. 1 yellow-eyed with thumbs: 1 red-eyed without thumbs.
16. The map distances for four linked genes are as follows: A is 22mu from B, B is 7mu from C, C is 9mu from D, B is 2mu from D, A is 20mu from D, and A is 29mu from C. Based on these data, what is the order of these four genes on the chromosome?
a. ABCD
b. ADBC
c. ABDC
d. BADC
e. CADB
17. In birds and butterflies ____ for sex chromosome inheritance.
a. males are XY and females are XX
b. males are ZZ and females are ZW
c. males are ZY and females are XW
d. males are XX and females are XY
e. males are ZW and females are ZZ
18. In humans, normally if ____ then the SRY gene switches development toward ____ at an early point in embryonic development.
a. a Y chromosome is present; maleness
b. an X chromosome is present; femaleness
c. two X chromosomes are present; femaleness
d. no X chromosome is present; maleness
e. a Y chromosome is present; femaleness
19. In Drosophila melanogaster there is a sex-linked gene for eye color that is found only on the X chromosome. The allele for red eye color (Xw+) is dominant over the allele for white eye color (Xw). You examine a vial of 100 flies that are all offspring from a single genetic cross. You see only red-eyed females and white- eyed males present. The genotypes of the parents were
a. Xw+Xw+; XwY.
b. Xw+Xw; XwY.
c. XwXw; Xw+Y.
d. Xw+Xw; Xw+Y.
e. XwXw; XwY.
20. In placental mammals such as humans the dosage compensation mechanism to essentially equalize expression of sex-linked genes in males and females is
a. doubling the gene expression for most genes on the X chromosome in males.
b. doubling the number of X chromosomes in males early in embryonic development in all cells except for precursors of sex cells.
c. having all major genes on the X chromosome also present on the Y chromosome.
d. halving the gene expression for most genes on each X chromosome in females.
e. inactivation of one of the two X chromosomes in most body cells of females.
Explanation / Answer
Q1). When did Gregor Mendel perform his experiments with garden peas?
a. in the 1860s, the same decade as the United States' Civil War
Q2.) Mendel crossed true-breeding plants having yellow peas with plants having green peas. The resulting plants all had yellow peas. An F1 cross resulted in 3/4 of the plants having yellow peas and 1/4 of the plants having green peas. What does this tell you about the alleles for color?
c. yellow is the dominant color
Q3). A testcross is used to
a. determine if a parent with a dominant trait is heterozygous or homozygous.
Q4). A parent has a genotype of RrYy. What is the probability of having a gamete with the RY genotype?
b. 1/4
Q5). Which individual established the connection between genes, meiosis, and fertilization?
e. Walter Sutton
Q6). Your parents are both heterozygous for the recessive disorder phenylketonuria (PKU). What is the probability that you will have the disorder?
a. 25% regardless of the health of your 3 siblings
Q7). A cross is done between parents with genotypes aaBbCc and aaBbcc. What is the probability that offspring will have the same genotype as the first parent?
b. ¼
Q8). You cross a pink snapdragon (CRCW) with a white snapdragon (CWCW). What percentage of the progeny will be red?
a. 0%
Q9). Your father has type B blood. Your mother has type O blood. You get tested and learn that your blood is also type O. What does this tell you?
c. Your father's genotype is IBi and your mother's genotype is ii.
Q10). The different alleles in human blood type are a demonstration of
c. dominance and codominance.
Q11). Mouse pigmentation is subject to epistasis of the B alleles by the d alleles. B (black) is dominant over b (brown). D is dominant over d. Homozygous d is epistatic to the black and brown genes. Given this information, what genotypes give you a white mouse?
e. BBdd and Bbdd
Q12). Linked genes are
d. genes that do not sort independently due to their being physically near each other on the same chromosome.
Q13). Exceptions to the principle of independent assortment were discovered and explained by ____ as resulting from genes being physically associated with each other on the same chromosome.
c. Morgan
Q14). Genetic studies of an animal show that eye color is controlled by an autosomal gene with the dominant allele (R) for red eye color and the recessive allele (r) for yellow eye color. A second autosomal gene has the dominant allele (T) leading to paws with thumbs while the recessive allele (t) codes for paws without thumbs. The genetic cross RRTT rrtt creates offspring with genotype RrTt. One of those dihybrids is mated in a testcross (RrTt rrtt). Based on the principle of independent assortment the testcross should produce offspring with the phenotype ratio
b. 1 red-eyed with thumbs: 1 yellow-eyed with thumbs: 1 red-eyed without thumbs: 1 yellow-eyed without thumbs.
Q15). Genetic studies of an animal show that eye color is controlled by an autosomal gene with the dominant allele (R) for red eye color and the recessive allele (r) for yellow eye color. A second autosomal gene has the dominant allele (T) leading to paws with thumbs while the recessive allele (t) codes for paws without thumbs. The genetic cross RRTT rrtt creates offspring with genotype RrTt. One of those dihybrids is mated in a testcross (RrTt rrtt). If the two genes are completely linked (no recombination occurs between them), then the testcross should produce offspring with the phenotype ratio).
c. 1 red-eyed with thumbs: 1 yellow-eyed without thumbs.
Q16). The map distances for four linked genes are as follows: A is 22mu from B, B is 7mu from C, C is 9mu from D, B is 2mu from D, A is 20mu from D, and A is 29mu from C. Based on these data, what is the order of these four genes on the chromosome?
b. ADBC
Q17). In birds and butterflies ____ for sex chromosome inheritance.
b. males are ZZ and females are ZW
Q18). In humans, normally if ____ then the SRY gene switches development toward ____ at an early point in embryonic development.
a. a Y chromosome is present; maleness
Q19). In Drosophila melanogaster there is a sex-linked gene for eye color that is found only on the X chromosome. The allele for red eye color (Xw+) is dominant over the allele for white eye color (Xw). You examine a vial of 100 flies that are all offspring from a single genetic cross. You see only red-eyed females and white- eyed males present. The genotypes of the parents were
c. XwXw; Xw+Y.
Q20). In placental mammals such as humans the dosage compensation mechanism to essentially equalize expression of sex-linked genes in males and females is
e. inactivation of one of the two X chromosomes in most body cells of females.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.