The rechrystallized asprin is 0.050% salicylic acid by mass. Determine the numbe

Question

The rechrystallized asprin is 0.050% salicylic acid by mass. Determine the number of moles of salicylic acid for each trial.

In the lab we titrated the sample with a standard NaOH solution the average molarity was determined to be 0.1019 M.

We ran two trials and I need separate answers for each. Here is the data:

                             Mass of Sample                     Volume NaOH            Total Moles Acid

Trial 1                       0.2300 g                                   13.9 mL                      0.001410

Trial 2                       0.2100 g                                    11.1 mL                     0.001131

If you could explain how and why you got the answers you did it would be a big help. Thanks in advance.

Explanation / Answer

trial 1 - no of moles of NaOH - 13.9*0.1019 = 1.42 milimoles = moles of acid in sample

trial 2- no of moles of NaOH - 11.1*0.1019 = 1.31 milimoles = moles of acid in sample

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.