A steel container with a volume of 500.0 mL is evacuated, and 25.0 g of CaCO3 is

Question

A steel container with a volume of 500.0 mL is evacuated, and 25.0 g of CaCO3 is added. The Container and contents are then heated to 1500 K, cuasing the CaCO3 to decomposed completely, according to the equation CaCO3(s)-->CaO(s) + CO2(g): (a) Using the ideal gas law and ignoring the volume of any solids remaining in the container, calculate the pressure inside the container at 1500 K. (b)Now make a more accurate calculation of the pressure inside the container. Take into account the volume of solid CaCO (density =3.34g/mL) in the containee, and use thed van der Waals equation for CO2(g) are: a=3.59(L^2.atm)/mol^2, and b=0.0427L/mol.

Explanation / Answer

pv=nrt ,p=nrt/v

25 gm =0.25 mole

t=1500

v=500

p=1526.25 pa

density =3.34 volume

25/3.34=7.48

remaining volume =500-7.48 ml=492.52

p=6330.2 pa

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