I found the reaction but what is K When the oxide of generic metal M is heated a
ID: 633326 • Letter: I
Question
I found the reaction but what is K
When the oxide of generic metal M is heated at 25.0 degree C, only a negligible amount of M is produced. MO2(s) M(s) + O2(g) delta G degree = 289.4 kJ/mol When this reaction is coupled to the conversion of graphite to carbon dioxide, it becomes spontaneous. What is the chemical equation of this coupled process? Show that the reaction is in equilibrium, include physical states, and represent graphite as C(s). MO2(s) + C(s) M(s) + CO2(g) What is the thermodynamic equilibrium constant for the coupled reaction? K =Explanation / Answer
Delta(Go) = -RTln(K)
=> ln(k) = -Delta(Go)/RT
=-(289.4-394.3)*10^(3)/(8.314*298) = 42.34
[-394.3 KJ/mol is the gibbs free energy for formation of CO2 from graphite]
=> K = e^(42.34)
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