Trial 1 Mass of Water: 124.229g Mass of NaOH: 3.350g Total Mass: 127.579g Mole o

ID: 632848 • Letter: T

Question

Trial 1

Mass of Water: 124.229g

Mass of NaOH: 3.350g

Total Mass: 127.579g

Mole of NaOH: .0838mol

Initial temp: 22.5 Celsius

Final temp: 29.5 Celsius

Change in temp: 7 Celsius

Trial 2

Mass of Water: 121.697g

Mass of NaOH: 5.129g

Total Mass: 126.826g

Mole of NaOH: .128mol

Initial temp: 23.2 Celsius

Final temp: 29.6 Celsius

Change in temp: 6.4 Celsius

What is the delta H dissolution for each?

The average delta H dissolution?

The accepted delta H dissolution?

Percent error?

please show work so i can understand

1).q = m*(dt)*c =124.229*7*4.184

=3638.419

delata h dissolution= q/mole of NaOH=43.42 Kj/mole.

2). same as 1). q=3258.76

delata h dissolution = q/mole of NaOH=25.46 Kj/mole

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.