Data starts here. Solution 1: 3 mL of CuSO4 and 1 mL H2O Solution 2: 2 mL of CuS
ID: 632808 • Letter: D
Question
Data starts here.
Solution 1: 3 mL of CuSO4 and 1 mL H2O
Solution 2: 2 mL of CuSO4 and 3 mL H2O
Solution 3: 2 mL of CuSO4 and 8 mL H2O
Solution 1: 2 mL of CuSO4 and 13 mL H2O
Absorbance (635 nm) for solution 1: 0.194
Absorbance (635 nm) for solution 2: 0.104
Absorbance (635 nm) for solution 3: 0.050
Absorbance (635 nm) for solution 4: 0.025
Absorbance from fitrate a (done in lab): .086
Absorbance from fitrate a (done in lab): .017
Absorbance from fitrate a (done in lab): .009
Absorbance from fitrate a (done in lab): .040
[Cu2+] in solution 1: 0.15 M
[Cu2+] in solution 2: 0.08 M
[Cu2+] in solution 3: 0.04 M
[Cu2+] in solution 4: 0.03 M
CuC4H4O6 (s) <--> Cu2+ (aq) + C4H4O62- (aq)
A = m * [Cu2+] + (y-intercept) and
A = 1.33 * [Cu2+] - 00.51
[Cu2+] in filtrate a: 0.065
[Cu2+] in filtrate b: 0.013
[Cu2+] in filtrate c: 0.0068
[Cu2+] in filtrate d: 0.030
Data ends here.
Question #1a
Calculate Ksp in filtrate a:
Calculate Ksp in filtrate b:
Question #1b
Calculate molar solubility in filtrate a:
Calculate molar solubility in filtrate b:
Calculate molar solubility in filtrate c:
Calculate molar solubility in filtrate d:
Explanation / Answer
That answer is wrong.
moles does not equal concentration/volume.
the number of moles is equal to concentration(mol/L) X volume (L); L cancel out leaving you with the number of moles.
concentration is equal to the number of moles per liter. therefore that c=n*v is wrong also
HOW IS YOURS THE BEST ANSWER?
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.