24.02 Dissolving Precipitates by Forming Complex Ions Part A What is the maximum
ID: 632704 • Letter: 2
Question
24.02 Dissolving Precipitates by Forming Complex Ions Part A What is the maximum [Ag(NH3)2+] that can be obtained by dissolving AgCl in 3.9 M ammonia? Give your answer to two significant figures. Do not round until the final answer. [Ag(NH3)2+] = M Try Again; 12 attempts remaining Part A What is the maximum [Ag(NH3)2+] that can be obtained by dissolving AgCl in 3.9 M ammonia? Give your answer to two significant figures. Do not round until the final answer. [Ag(NH3)2+] = M Try Again; 12 attempts remaining [Ag(NH3)2+] = M Try Again; 12 attempts remaining Part B For another silver salt, AgSCN, Ksp = 1 Part B For another silver salt, AgSCN, Ksp = 1 [Ag(NH3)2+] = MExplanation / Answer
prtA:a. AgC2H3O2(s)
b. Al(OH)3(s) ? Al3+(aq) + 3 OH?(aq) Ksp = [Al3+] [OH?]3
c. Ca3(PO4)2(s) ? 3 Ca2+(aq) + 2 PO43?(aq) Ksp = [Ca2+]3 [PO43?]2
a. Ag2CO3(s) ? 2 Ag+(aq) + CO32? (aq) Ksp = [Ag+]2 [CO32?]
?
Ag+(aq) + C2H3O2?(aq) Ksp = [Ag+] [C2H3O2?]
b. Ce(IO3)3(s) ? Ce3+(aq) + 3 IO3? (aq) Ksp = [Ce3+] [IO3?]3
c. BaF2(s) ? Ba2+(aq) + 2 F-(aq) Ksp = [Ba2+] [F?]2
SOLUBILITY AND COMPLEX ION EQUILIBRIA
prt B:4. 7.0
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