please explain how you get the answer! thank you Suppose a population of flour b

Question

please explain how you get the answer! thank you

Suppose a population of flour beetles has 1,000 individuals. Normally the beetles are red; however, this population is polymorphic for a mutant autosomal body color, black, designated by bb. Red is dominant to black, so BB and Bb genotypes are red. Assume the population is at Hardy–Weinberg equilibrium, with equal frequencies of the two alleles. What would be the allele frequencies if a population bottleneck occurred and only four individuals survived: one female red heterozygote and three black males? A) 0.125 red; 0.875 black B)0.875 red; 0.125 black C) 0.25 red; 0.75 black D) 0.75 red; 0.25 black E) 0.5 red; 0.5 black

Explanation / Answer

The number of individuals survived after population bottleneck are four, one female red heterozygote (bB) and three black males (bb).

Given that the allele frequencies are equal.

Now, the proportion of homozygous recessive individuals in the population = 3/4 = 0.75 = q2.

Thus, the frequency of b allele or q = 0.87 or approximately 0.875.

The frequency of B allele or p = 1-q = 1-875 = 0.125.

Thus, the correct option is A) 0.125 red; 0.875 black

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