1))According to the following reaction, how many grams of hydrogen gas are neces

Question

1))According to the following reaction, how many grams of hydrogen gas are necessary to form 0.475 moles nitrogen gas? nitrogen monoxide (g) + hydrogen (g) nitrogen (g) + water (l) 2))According to the following reaction, how many moles of carbon dioxide will be formed upon the complete reaction of 24.4 grams of carbon monoxide with excess water? carbon monoxide (g) + water (l) carbon dioxide (g) + hydrogen (g) 3))According to the following reaction, how many moles of mercury will be formed upon the complete reaction of 26.5 grams of mercury(II) oxide? mercury(II) oxide (s) mercury (l) + oxygen (g)

Explanation / Answer

1) 2 NO(g) + 2 H2(g) ------>N2(g) + 2 H2O(g) 2 moles oh hydrogen produce 1 mole of nitrogen therefore for producing 0.475 moles oh nitrogen we need = 0.475/2 moles of hydrogen = 0.2375 moles hydrogen required in grams = 2*0.2375 gms = 0.475 gms 2) CO+H20H2+CO2 from eqaution we can see that 1 mole of CO converts to 1 mole of CO2 if CO is limiting reagent therefore moles of CO2 = moles of C0 = 24.4/28 = 0.871428571 moles 3) 2HgO + heat ==> 2Hg (liquid) + O2 (gas) rom eqaution we can see that 1 mole of HgOconverts to 1 mole of Hg therefore moles of HgO taken = moles of Hg formed after full reaction = 26.5/216.59 = 0.122350986 moles

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