The results below are from a titration lab utilizing 25mL of .1M acetic acid whi

Question

The results below are from a titration lab utilizing 25mL of .1M acetic acid which was titrated with the NaOH solution of volume and molarity shown below. Please show how to get the correct pH at equivalence to compare with indicator change, I am unsure whether I am doing this right. It is not necessary to show all answers just a good example of the process so that I can do all of the calculation. Indicator mL of NaOH Molarity of NaOH Alizarin Yellow 18.7 0.116 Alizarin Yellow 16.9 0.28 Alizarin Yellow 19.62 0.1252 Alizarin Yellow 25.4 0.134 Bromothymol Blue 36.85 0.227 Bromothymol Blue 29.05 0.113 Bromothymol Blue 18.25 0.125 Indigo Carmine 53.01 0.227 Indigo Carmine 21.57 0.113 Indigo Carmine 24.25 0.125 Methyl Orange 9.7 0.187

Explanation / Answer

i hope this will help

http://www.avogadro.co.uk/chemeqm/acidbase/titration/phcurves.htm

gd luck

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