consider the ammonia gas formation reaction at 298K 3/2 H2(g)+1/2N2(g)--> NH3(g)

Question

consider the ammonia gas formation reaction at 298K 3/2 H2(g)+1/2N2(g)--> NH3(g) a) calculate the reaction enthalpy for the formation of ammonia using the following info: 3H(g)+N(g)--> NH3 (g) delta H=-1172.4 kJ/mol 1/2 H2(g)-->H(g) delta H=217.9 kJ/mol 1/2 N2(g)---> N(g) delta H=472.6 kJ/mol b) what is the delta U at 298 K for the ammonia formation reaction? c) use the temperature dependent heat capacities from NIST WebBook to compute delta H rc at 400K

Explanation / Answer

FOLLOW THIS To get the entropy of formation you have to use your table of standard entropy, heat and energies. H2(g) is zero for H2O(g) you have to use the reaction H2(g)+(1/2)O2(g)--> H2O(g) you take the standard entropy of products minus reactants and you get -44.385 for NH3(g) you use the reaction (1/2)N2(g) + (1/3) H2(g)--> NH3(g) you do the same as before take the entropy of products minus reactants and you end up with -99.3 for O3(g) you use the reaction (3/2)O2(g)-->O3(g) and you end up with -68.725

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