n this experiment a hot metal block at 100oC is added to cold water in a calorim

Question

n this experiment a hot metal block at 100oC is added to cold water in a calorimeter. The heat lost by the metal block equals the heat gained by the water and the two end up at the same temperature. In one experiment, the mass of the metal block is 84.4 grams, the volume of water used is 70.9 mL, the temperature of the cold water extrapolated to the time of mixing is 21.0oC, and the temperature of the metal block and water extrapolated back to the time of mixing is 26.1oC. The specific heat of water is 4.184 J K-1g-1 1.) How much heat is gained by the cold water? Heat gained by cold water = _________J 2.) What is the specific heat of the metal? Specific heat of the metal = _______J K-1g-1 3.) According to the Law of Dulong and Petit, what is the molar mass of the metal? Molar mass = ______g mol-1 Please answer all three parts!

Explanation / Answer

1) heat gained by cold water = 4.18 x70.9x (26.1-21) = 1511.446 Joules 2) specific heat of metal = (1511.446)/(84.4x(100-26.1)) = 0.24233 Joules/gmK 3) C = 3R/M , M = 3R/C = 3 x8.314 /0.2423 = 102.925 gm/mol

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