n the circuit shown on the right, R1 has a resistance of 2.5 k2, R2 has a resist

Question

n the circuit shown on the right, R1 has a resistance of 2.5 k2, R2 has a resistance of 3 kQ, and R3 has a resistance of 1 k and R4 has a resistance of 1.5 k2. A power supply provides 15 V of emf. R2 R3 R4 A.(2 pts.) Find the total current through the circuit. 15v 2.2A B. (2 pts.) Write the Kirchoff's loop and junction equations for the circuit. C. (2 pts.) Find the voltage difference across each resistor. 2.5 D.(2 pts.) Find the current through each resistor -1:571 :3.22 Len Ye E. (2 pts.) Find the power dissipated through each resistor R, 2.2 . 3.22 : 7.01 72w

Explanation / Answer

1/R234 = 1/R2 + R3 + R4

1/R234 = 1/3 + 1/1 + 1/1.5

R234 = 0.5 kohm

Rnet = R1 + R234

= 2.5 + 0.5

= 3 kohm

A) total current through the ckt, I = V/Rnet

= 15/(3*10^3)

= 5*10^-3 A or 5 mA

B) junction rule, I1 = I2 + I3 + I4

Kirchoff's voltage rule

V - I1*R1 - (I1 + I2 + I3)*R234 = 0

C) V1 = I1*R1

= 5*10^-3*2.5*10^3

= 12.5 V

V2 = 15 - 12.5 = 2.5 V

V3 = 2.5 V

V4 = 2.5 V

D) I1 = I = 5*10^-3 A

I2 = V2/R2 = 2.5/(3*10^3) = 0.83*10^-3 A

I3 = V3/R3 = 2.5/(1*10^3) = 2.5*10^-3 A

I4 = V4/R4 = 2.5/(1.5*10^3) = 1.67*10^-3 A

E)

P1 = I1^2*R1 = (5*10^-3)^2*2.5*10^3 = 0.0625 W
P2 = I2^2*R2 = (0.83*10^-3)^2*3*10^3 = 0.00207 W
P3 = I3^2*R3 = (2.5*10^-3)^2*1*10^3 = 0.00625 W
P4 = I4^2*R4 = (1.67*10^-3)^2*1.5*10^3 = 0.00418 W

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