The vapor pressure, P , of a certain liquid was measured at two temperatures, T.

Question

The vapor pressure, P , of a certain liquid was measured at two temperatures, T. DATA T(K) P(K Pa) 225 3.12 625 7.52 Graphically determine the enthalpy of vaporization. For this liquid what points would you plot? Round 3 sig figs for x values, and 4 sig figs for y values. (x,y)Point 1 :(X) number (Y) number (x,y)Point 2 :(X) number (Y) number Then determine the rise, run, and slope if line formed by these points. rise= run= slope= What is the enthalpy of vaporization of this liquid? = _________J/mol PLEASE SHOW WORK STEP BY STEP

Explanation / Answer

Follow these steps and change values where needed Let T(K) be x and P(kPa) your y Point 1: x1= 1/225= .00444, y1=ln(3.11)= 1.135 Point 2: x2= 1/775= .00129, y2=ln(6.56)= 1.881 Rise= y2-y1= 1.881-1.135= .746 Run= x2-x1= .00129-.00444= -.00315 Slope= y2-y1/x2-x1= .746/-.00315= -236 deltaHvap= mxR= 236x8.314= 1962 J/mol (R is a constant)

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