The vapor pressure of liquid ethanol , C 2 H 5 OH , is 100 . mm Hg at 308 K. A s
ID: 1069432 • Letter: T
Question
The vapor pressure of liquid ethanol, C2H5OH, is 100. mm Hg at 308 K.
A sample of C2H5OH is placed in a closed, evacuated 529 mL container at a temperature of 308 K. It is found that all of the C2H5OH is in the vapor phase and that the pressure is 67.0 mm Hg. If the volume of the container is reduced to 344 mL at constant temperature, which of the following statements are correct?
Choose all that apply.
The pressure in the container will be 103 mm Hg.
Some of the vapor initially present will condense.
Liquid ethanol will be present.
Only ethanol vapor will be present.
No condensation will occur.
Explanation / Answer
since the pressure is low and temperautre is also not very less, ideal gas law can be applied, hence
from P1V1= P2V2 ( at constant temperature)
529*67= 344*P2, P2= pressure during reduction in volume
P2= 103.022 mm Hg
since the pressure is more than the vapor pressure, some of the ethanol vapor condenses and becomes a liquid so as to reach a condition where in partial pressure of vapor = vapor pressure of liquid.
so some liquid ethanol will be there, the pressure will be 103.022 mm Hg. Some of the vapor starts condensing
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