a) Calculate the change in entropy (deltaS) when one mole of diamond is heated f

Question

a) Calculate the change in entropy (deltaS) when one mole of diamond is heated from a temperature of 0 K to 400 K at a constant pressure of 1 bar. The temperature-dependent heat capacity of diamond is Cv ? 2.9x10-7 T3 J/(mol K), where T is the absolute temperature in K. b) Given that the entropy of diamond is zero at 0 K, calculate its absolute molar entropy at 400 K from the above result.

Explanation / Answer

entropy change= For solid and liquid, Tds = dh - vdp = du + pdv, dp ~dv ~0 --> incompressible substance Tds = dh/T = du/T ds = dh/T = du.T ds = (c/T)dT ?s = c*ln(Tf/Ti) ?S = nc*ln(Tf/Ti) --> incompressible substance with sensible heat, temperature change,

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