A galvanic cell is composed of these two half cells, with the standard reduction

Question

A galvanic cell is composed of these two half cells, with the standard reduction potential shown: Co2+(aq) + 2e- <--------> Co(s) -0.28 volt Cd2+(aq)+ 2e- <----------> Cd(s) -0.40 volt The actual concentrations are: Co^2+(aq) = 0.00100M, Cd^2+= 0.100M. What is the potential of this galvanic cell? Step by step solution and i will give 5 stars! NEEDS TO BE STEP BY STEP AND VERY CLEAR OR DON'T BOTHER RESPONDING. This problem is also different than the one easily found on google so don't just copy and paste without thinking.

Explanation / Answer

The cell reaction is:
Cd + Co(2+) ==> Co + Cd(2+), E° = 0.12V
G = -nFE = -nFE° + RT*Ln Q
= -2*96485*0.12+8.314*298*ln(0.100/0.001)
= -11.7 kJ

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