A 12.0 L helium tank is pressurized to 29.0 atm. When connected to this tank, a

Question

A 12.0 L helium tank is pressurized to 29.0 atm. When connected to this tank, a balloon will inflate because the pressure inside the tank is greater than the atmospheric pressure pushing on the outside of the balloon. Assuming the balloon could expand indefinitely and never burst, the pressure would eventually equalize causing the ballon to stop inflating. What would the volume of the ballon be when this happens? Asssume atmospheric pressure is 1.00 atm. Also assume ideal behavior and constant temperature. Please show steps.

Explanation / Answer

(12.0 L) x (29.0 / 1.00) = 348 L total at 1 atm But there are still 12 L in the tank, so the volume of the balloon is 348- 12 = 336 L

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