In monkeys, black coat color (B) is dominant over brown color (b). A population

Question

In monkeys, black coat color (B) is dominant over brown color (b). A population of monkeys was found to be composed of 67 brown coated individuals and 119 black coated individuals.

What is the frequency of the b allele in this population?

What is the frequency of the B allele in this population?

Based upon the HardyWeinberg formula, what proportion of the     population is expected to have the genotype BB?

d. Based upon the HardyWeinberg formula, what proportion of the population is expected to bave black coat color?

e.Based upon the HardyWeinberg formula, how many individuals in this population would be expected to have the genotype Bb?

Explanation / Answer

Given that, B (black) is dominant to brown color (b). Number of individuals with brown coat = 67.

The proportion of individuals with the brown coat = 67/ 119+ 67 = 0.36 = q2; q = 0.6

Since, p + q = 1, p = 1- 0.6 = 0.4.

a. Thus, the frequency of allele B is (p) = 0.4

b. The frequency of allele b is (q) = 0.6

c. The proportion of population with the BB genotype = p2 = 0.4*0.4 = 0.16 (or 30 in the total population)

d. The proportion of individuals with the black coat color = Individuals homozygous for B allele and heterozygotes = p2 + 2pq = 0.16 + 2* 0.4* 0.6 = 0.16+ 0.48 = 0.64 = 119. (Exactly 119.68).

e. Number of individuals with the genotype Bb = 2pq = 2* 0.6* 0.4 = 0.48 = 89 (approximately)

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