Balance the following redox reaction by the method of half-reactions: SeO3(aq) +
ID: 605622 • Letter: B
Question
Balance the following redox reaction by the method of half-reactions: SeO3(aq) + I-(aq) --> Se(s) + I2(aq)Explanation / Answer
you have not mentioned the medium for this reaction so i am assuming the reaction was in acidic medium ... oxidation half reaction... I- -------------> I2 balance atoms... 2I- ----------> I2 balance charge... 2I- ----------> I2 + 2e- .....(1) this is balanced oxidation half reaction... reduction half reaction... SeO3 -------> Se balance oxidation number.. SeO3 + 6e --------> Se now balance charge by adding H+... SeO3 + 6e- + 6H+ --------> Se now balance oxygen by adding H2O SeO3 + 6e- + 6H+ ----------> Se + 3H2O ...(2) this is balanced reduction half rection... multiply (1) by 3 and add in (2) 6I- ----------> 3I2 + 6e- SeO3 + 6e- + 6H+ ----------> Se + 3H2O ------------------------------------------------- 6e- will cancel out from both sides... 6I- + SeO3 + 6H+ --------> 3I2 + Se + 3H2O this is the balanced redox reaction
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