RT 18 sHEET 2 Date x) What species are present in 0.1 M HCI and NaOll solutions?

Question

RT 18 sHEET 2 Date x) What species are present in 0.1 M HCI and NaOll solutions? Write equations to describe the reactions that yield these species. Species preseat Equation NaOH(aq) (b) The effect of the solvent Category Conductivity No ions Few lons Many ions Toluene, C,Hgl HCI in toluene) or CH,COOH in toluenenon Aqueous layer after mixing with HCI (in toluene) for CHyCOOH in toluene) Why is the conductivity of HCI (or CH COOH) different in the two solvents? What causes this difference? (c) Correlating chemical and conductivity behavior () Compare the rates of reaction of CaCO,(s) with 6 M acetic acid and 6 M hydrochloric acid. The reaction of CaCO, with an acid, HA, is 2 HAlaq) + Caco,(s) Ca2+(aq) + 2 ATaq) + CO2(g) + H,01) (i) Compare the rates of reaction of Zn(s) with 6 N CH,COOH and 6 M HCL. The reaction of zinc with an acid, HA, Is (ii) Is there a correlation between the rates of the chemical reactions of 6 M CH,COOH and 6 the conductivities observed for CH,COOHfaq) and HCaq) in part 1(a)? Suggest an explanation. 18-9

Explanation / Answer

The HCl in an aqueous medium will have conductivity the difference is because The tolune is a non polar solvent, remember the old rule "like dissolves like" so Toluene will not dissolve HCl since HCl is polar so the HCl will not dissociate into ions H+ and Cl- that makes conductivity, many ions will be present

When an aqueous layer form the HCl will dissociate because the layer will be polar so the main reason of the difference in conductivity is polarity

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