Resources « previous | 4 of 6 | next art A When a U nucleus is bombarded by neut

Question

Resources « previous | 4 of 6 | next art A When a U nucleus is bombarded by neutrons (in) it undergoes a fission reaction, resulting in the formation of two new nuclei and neutrons. The following equation is an example of one such fission process: 92 Enter the isotope symbol for the barium (Ba) nucleus in this reaction Express your answer as an isotope. Hints Hint 1. How to approach the problem The uranium-235 isotope undergoes a neutron capture followed by a fission reaction. The first consideration is the type of nuclear decay. In this reaction the only decay is the splitting of the nucleus with the subsequent release of neutrons. Therefore, the number of protons does not change from the left side of the equation to the right. Use this as the starting point of your calculation, and keep in mind that the total number of nucleons on the right side of the equation must equal the total number of nucleons on the left.

Explanation / Answer

Let the product be X

Balance mass number on both sides

mass of U + mass of n = mass of Kr + mass of n + mass of X

1*235 + 1*1 = 1*94 + 3*1 + M

M = 139

Balance atomic number on both sides

atomic of U + atomic of n = atomic of Kr + atomic of n + atomic of X

1*92 + 1*0 = 1*36 + 3*0 + A

A = 56

Atomic number 56 is for element Ba

So, the product is

139-Ba

Answer:

A = 139

Z = 56

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