Resou 4/10/2018 11:55 PM -Print 0,100 Gradebook O A ?Calcuator ?Penodic Table Qu

Question

Resou 4/10/2018 11:55 PM -Print 0,100 Gradebook O A ?Calcuator ?Penodic Table Question 16 of 25 Ava Due Late Sapling Learning subr A certain indicator, HA, has a Ka value of 2.5 × 10.. The protonated form of the indicator is blue and the ionized form is yellow What is the pKa of the indicator? Point Grade Descr Policie You ca , You ca give up You ca until yo You los answer attempt What is the color of this indicator in a solution with pH - 47 0 yellow blue o eText O Help W Hin "?Check Answer 0 Next ?Er

Explanation / Answer

Ka = 2.5*10-6

pKa = -logKa = -log2.5*10-6 = 5.6

pKa = 5.6

For pH = 4,

pH<pKa

So, the ionized form of the indicator exists. (A-)

Yellow color.

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