A mechanism for the hydrogenation of ethylene, C,H., with hydrogen gas in the pr

Question

A mechanism for the hydrogenation of ethylene, C,H., with hydrogen gas in the presence of Pd/C is depieted below proceeding from step 1 through step 5. Use the illustrations to answer the questions 1-4. 1. H, (g) and C.H,(g) above Pd surface 6.C2H, product closeup new hydrogens 2. H2 absorbs onto Pd 5.C H, (g) leaves Pd surface 3. C2H, absorbs onto Pd 4. One H bonds to Carbon 1, what happens when the Hz molecules interact with the Palladium surface in steps 192? State which bonds that are broken and formed. 1pt

Explanation / Answer

Hydrogenation reaction

1. H2 molecule gets adsorbed on the Pd surface in steps 1-->2. The bond between H-H is broken.

2. When ethylene interacts with the palladium surface, the C=C bond gets broken and it attaches to the Pd surface.

3. The hydrogens which were adsorbed on the Pd surface are added to the ethylene carbon in these steps.

4. This is a concerted process, wherein the two hyrogens are added on the two carbons from the same side and we get a syn-addition product.

5. Dichloromethane is used as solvent for the reaction

a. another name for it is methylchloride

b. Both the compounds are organic and are thus soluble in dichloromethane.

6. saturated and unsaturated fats

a. Saturated fats would have higher melting point as more heat is needed to break the packing.

b. ability to pack enhances the intramolecular forces and thus affect the melting point of saturated and unsaturated fats.

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