Hydrogen gas reduces No to N2 in the following reaction: 2H2(g) + 2NO (8) = 2H2O
ID: 589307 • Letter: H
Question
Hydrogen gas reduces No to N2 in the following reaction: 2H2(g) + 2NO (8) = 2H2O(g) +N2(8) The initial reaction rates of four mixtures of H2 and NO were measured at 1500°C with the following results: Experiment (H2lo (M) [NO]0 (M) Initial Rate (M/S) 0.212 0.136 0.0325 0.212 0.272 0.065 0.424 0.544 0.51 0.848 0.544 2.0 6th attempt Part 1 (1 point) o Feedback Choose the correct rate law for the reaction at 1500°C. O Choose one: O A. rate =k[H;][NO] B. rate = k[H] C. rate =k[43][NO]? rate =k[1,]?[no] • D. Part 2 (1 point) * Feedback O See Hint Determine the rate constant for the reaction at 1500°C. O 1.61 M*1Explanation / Answer
From experiment 1 and 2, we can see that when the concentration of NO is doubled by keeping the concentration of H2 unchanged, reaction rate also doubled. Therefore, the reaction is first order w.r.to NO
From experiment 3 and 4, we can see that when the concentration of H2 is doubled by keeping the concentration of NO unchanged, reaction rate become 4 times. Therefore, the reaction is second order w.r.to H2
Therefore, rate law is,
Rate = k [H2]2[NO]
Rate constant k = Rate/[H2]2[NO]
= 0.0325/(0.2122 x 0.136) = 5.317 M-2 s-1
K = 5.317 M-2 s-1
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