west.cengagenow.com pts 2req Use the References to access impertant values if ac
ID: 588622 • Letter: W
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west.cengagenow.com pts 2req Use the References to access impertant values if aceded for this question. 1 pts 2req What is the calculated value of the cell potential at 298K for an electrochemical cell with the following reaction, when the Cl pressure is 2.59 10atm the Cr concentration is 1.05M, and the Hg concentration is 1.30M ? 7 pts 1 pts 2req 1 pts 2req 3 pts 2recq 1 pts 2req 7 pts 2req 8 pts 2req 7 pts 2req Answer The cell reaction as written above is spontaneous for the concentrations given: Submit Answer Retry Entire Group 9 more group attempts remaining 1 pts 2req 7 pts 2req 7 pts 2reqExplanation / Answer
Cl2 + Hg(l) ----> 2Cl-(aq) + Hg+2 (aq)
Cl2 + 2e- ----> 2Cl- Ered = 1.358 V
Hg -----> Hg+2 + 2e- Eoxi = -0.855 V
Net reaction is
Cl2 + Hg(l) ----> 2Cl-(aq) + Hg+2 (aq)
Eo = Eoxi + Red = 1.358 - 0.855 = 0.503 V
E = Eo - 0.0591/n *log Q
n = Number of electrons transferred in the reaction = 2
Q = [Hg+2] [Cl-]^2 / pCl2 = [1.3] [1.05]^2 / (2.59*10^-4 ) = 5533.7837
Substituting all
E = 0.503 - 0.0591 /2 * log 5533.7837 =0.39239 V
E = 0.39239 V
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