Print alculator_d Periodic Table Question 13 of 13 Sapling Learning Map e Fe2+ (

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Print alculator_d Periodic Table Question 13 of 13 Sapling Learning Map e Fe2+ (55.845 g/mol) content of a 2.457 g steel sample dissolved in 50.00 mL was determined by tiration with a standardized 0.110 M potassium permanganate (KMnO4. 158.034 g/mol) solution. The titration required 35.89 mL to reach the end point. What is the concentration of iron in the steel sample? Express your answer as grams of Fe per grams of steel (g Fe2/ g steel). MnO, + 8H + +5Fe2 + Mn2+ +5Fe3 + +4H20 Number g Fe /g steel Hint O Previous Give Up & View Solution 0 Check Answer Next Exit

Explanation / Answer

KMnO4 + 5 Fe2+ + 8 H+ 5 Fe3+ + Mn2+ + 4 H2O + K+

1L = 1000 mL

Titration required 35.89 mL

(0.03589 L KMnO4) x (0.110 M or mol/L KMnO4) x (5 mol Fe2+ / 1 mol KMnO4) x (55.845 g Fe/mol) =
1.102 g Fe

As the Fe2+ (55.845 g/mol) content of a 2.457 g steel sample,Therefore,Concentration of iron in steel sample is as follows

(1.102 g Fe) / (2.457 g steel) = 0.448 g Fe2+ / g steel

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