1a. A sample of methane gas at 292 K and 0.160 atm occupies a volume of 2.06 L.

Question

1a. A sample of methane gas at 292 K and 0.160 atm occupies a volume of 2.06 L. If the pressure of the gas is increased, while at the same time it is heated to a higher temperature, the final gas volume

a. will be smaller than 2.06 L.

b. will be larger than 2.06 L.

c. could be larger or smaller than 2.06 L depending on the final pressure and temperature.

1b. A sample of oxygen gas at 300 K and 2.26 atm occupies a volume of 4.45 L. If the gas is allowed to expand to a larger volume , while at the same time it is heated to a higher temperature, the final gas pressure

a. will be higher than 2.26 atm.

b. could be higher or lower than 2.26 atm depending on the final volume and temperature.

c. will be lower than 2.26 atm.

Explanation / Answer

1. (a)

We know that

PV = nRT

where
P = Pressure
V= Volume
n = number of moles
R = Gas constant
T = Temperature

Now,

PV = nRT

P/T = nR (1/V)

Here n and R are constant. So, if pressure and temperature of the gas is increased, that is neuminator and denominatore both are increased.

So, V will depend on the ratio of P/T.

So, answer is
c. could be larger or smaller than 2.06 L depending on the final pressure and temperature.

1. (b)

We know that

PV = nRT

where
P = Pressure
V= Volume
n = number of moles
R = Gas constant
T = Temperature

Now,

PV = nRT

V/T = nR (1/P)

Here n and R are constant. So, if volume and temperature of the gas is increased, that is neuminator and denominatore both are increased.

So, P will depend on the ratio of V/T.

So, answer is
b. could be higher or lower than 2.26 atm depending on the final volume and temperature.

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