A football tight end travels 14 m straight down the playing field in 2.1 s (in t

Question

A football tight end travels 14 m straight down the playing field in 2.1 s (in the positive direction). He is then hit and forced 2.5 m straight backwards in 1.8 s. He breaks the tackle and runs straight forward another 16 m in 4.4 s. Calculate the tight end's average velocity in the horizontal direction during the first interval, in meters per second. A numeric value is expected and not an expression, v_1 =___Calculate the tight end's average velocity in the horizontal direction during the second interval, in meters per second. Numeric: A numeric value is expected and not an expression. Calculate the tight end's average velocity in the horizontal direction during the third interval, in meters per second. Numeric: A numeric value is expected and not an expression. Calculate the tight end's average velocity in the horizontal direction for the entire motion, in meters per second. Numeric: A numeric value is expected and not an expression.

Explanation / Answer

Average velocity = total displacement / total time

i) Average velocity during first interval = 14 m / 2.1 s

= 6.67 m/s

ii) during second interval = - 2.5 / 1.8 = - 1.38 m/s

[ -ve sign for backward direction]

iii) during third interval = 16 / 4.4 = 3.63 m/s

iv) during entire motion = 14 - 2.5 +16 / 2.1 + 1.8+4.4

= 3.31 m/s

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