Latent heat questions I need help with 2 & 3. Thank you! Prelab 1: Explain in yo

Question

Latent heat questions

I need help with 2 & 3. Thank you!

Prelab 1: Explain in your own words the difference between latent heat and specific heat. Prelab 2: Skin can be burned by coming into contact with hot water or steam. For example, when 100°C water comes into contact with 37°C skin, heat is transferred to the skin and an injury occurs. As another example, when 100°C steam comes into contact with 37°C skin, a burn will occur as well. Which would cause a more severe burn, water at 100°C or an equal mass of steam at 100°C? Explain. Prelab 3: 20.0 g of ice at 0°C is added to 250.0 g of water at 25°C and allowed to melt. What is the final temperature of the water and melted ice? (Hint: The latent heat of fusion for water is 334 J/g and the specific heat of water is 4.184//(g·°C). Conservation of energy is useful here.)

Explanation / Answer

latent het of vaporisation of water 2264 KJ/Kg, it means that steam at 100 C will release 2264 KJ/Kg heat before converting to water at 100 C . it means that it will directly transmitted to the body cause severe burn than the water.

3.) Heat=mass X specific heat X change in temp
Heat of fusion for ice is 334 J/g
Let Y=final temp
Heat =mass X heat of fusion
heat=20 X 334 = 6680 J
6680 J heat is required to convert 20g of ice into water

intially total heat in 250g water at 25 C = mcT = 250*4.184*298 = 311708 J

remaining heat = 311708 - 6680 = 305028 J

equilirium temperature

mc(T-T2) = m1c(T1-T)

250*4.184(298 - T) = 20* 4.184(T-273)

T = 296.14 K

final temperature of water = 296.14 K

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