A parallel-plate capacitor has a capacitance of cj = 3.5 mu F when full of air a

Question

A parallel-plate capacitor has a capacitance of cj = 3.5 mu F when full of air and c_2= 34 mu F when full of a dielectric oil at potential difference of 12 V. Take the vacuum permittivity to be belongs to_0= 8.85 times 10^-12 C^2/(N.m^2). Be clear and concise. Typing work is highly suggested. Will upvote based on the quality of work done. Input an expression for the permittivity of oil e. What is the permittivity of the oil in C^2/(Nm^2)? How much more charge Delta q in C does the capacitor hold when filled with oil relative to when it's filled with air?

Explanation / Answer

The capacitance of capacitor in air C1=3.5µF

The capacitance of capacitor in dielectric of oil C2=34µF

The potential difference V=12 V

a.The expression for permittivity of oil =K0

Where K= C2/C1=34µF3.5µF

b.The permittivity of oil = K0=9.71X8.85X10-12 =85.9X10-12 c2/N-m2

c.The charge on the capacitor when the dielectric of oil Q= C2 V/K=34X12X10-6/9.71=42µC

                                                           

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